-5(x)=3x^2+5x

Solution for -5(x)=3x^2+5x equation:

-5(x)=3x^2+5x

We move all terms to the left:

-5(x)-(3x^2+5x)=0

We get rid of parentheses

-3x^2-5x-5x=0

We add all the numbers together, and all the variables

-3x^2-10x=0

a = -3; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-3)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-3}=\frac{0}{-6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-3}=\frac{20}{-6}
=-3+1/3
$